14x^2-160x-126=0

Solution for 14x^2-160x-126=0 equation:

14x^2-160x-126=0

a = 14; b = -160; c = -126;
Δ = b2-4ac
Δ = -1602-4·14·(-126)
Δ = 32656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32656}=\sqrt{16*2041}=\sqrt{16}*\sqrt{2041}=4\sqrt{2041}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-4\sqrt{2041}}{2*14}=\frac{160-4\sqrt{2041}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+4\sqrt{2041}}{2*14}=\frac{160+4\sqrt{2041}}{28}
$